A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

Question

Dr. Abubacker · Accepted Answer

[Solution from source] With no external force, momentum is conserved: 0.5 × 2 = 50 × v, so the man moves up at 0.02 m/s. The stone takes 10/2 = 5 s to reach the floor, in which the man rises 0.02 × 5 = 0.1 m, so he is at 10.1 m. Answering 10 m ignores the recoil; 9.9 m takes the recoil in the wrong direction. Answer (3).

Q. A man of 50 kg mass is standing in a gravity free space at a height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 m/s. When the stone reaches the floor, the distance of the man above the floor will be

Explanation

Reviewed by Dr. Abubacker

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