Q. The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
A) √2 T
B) T
C) T/√2
D) 2T
Explanation
[Solution from source] T = 2π√(M/k), so T ∝ √M. Doubling the mass gives T′ = √2 T. 2T would need four times the mass. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.