Q.
A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current. If it is to work as a voltmeter of 30 volt range, the resistance required to be added will be
A) 1000 Ω
B) 900 Ω
C) 1800 Ω
D) 500 Ω
Explanation
[Solution from source] Total resistance needed = V/I_g = 30/0.030 = 1000 Ω. Series resistance = 1000 − 100 = 900 Ω. 1000 Ω forgets to subtract the coil's own resistance. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.