Q.
A conducting circular loop is placed in a uniform magnetic field, B = 0.025 T with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of 1 mm s⁻¹. The induced emf when the radius is 2 cm is
A) 2 µV
B) 2π µV
C) π µV
D) (π/2) µV
Explanation
[Solution from source] φ = Bπr², so |ε| = Bπ·2r·(dr/dt) = 0.025 × π × 2 × 0.02 × 10⁻³ = π × 10⁻⁶ V = π μV. Forgetting the factor 2 from d(r²)/dt gives (π/2) μV. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.