A source S₁ is producing 10¹⁵ photons per second of wavelength 5000 Å. Another source S₂ is producing 1.02 × 10¹⁵ photons per second of wavelength 5100 Å. Then (power of S₂)/(power of S₁) is equal to

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Power = n·hc/λ. P₂/P₁ = (n₂/n₁)(λ₁/λ₂) = 1.02 × 5000/5100 = 1.00. 1.02 counts only the photon numbers and ignores the lower energy of longer-wavelength photons. Answer (2).

Q. A source S₁ is producing 10¹⁵ photons per second of wavelength 5000 Å. Another source S₂ is producing 1.02 × 10¹⁵ photons per second of wavelength 5100 Å. Then (power of S₂)/(power of S₁) is equal to

Explanation

Reviewed by Dr. Abubacker

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