Q.
A beam of cathode rays is subjected to crossed electric (E) and magnetic (B) fields. The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by (where V is the potential difference between cathode and anode)
A) E²/(2VB²)
B) B²/(2VE²)
C) 2VB²/E²
D) 2VE²/B²
Explanation
[Solution from source] No deflection means eE = evB, so v = E/B. Accelerated through V: eV = ½mv², so e/m = v²/(2V) = E²/(2VB²). The inverted forms come from writing v = B/E. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.