Q. The mass of a ⁷₃Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃Li nucleus is nearly
A) 23 MeV
B) 46 MeV
C) 5.6 MeV
D) 3.9 MeV
Explanation
[Solution from source] Binding energy = 0.042 × 931 ≈ 39.1 MeV. Per nucleon: 39.1/7 ≈ 5.6 MeV. 39 MeV would be the total, not per nucleon. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.