Q. For the reaction N₂O₅(g) → 2NO₂(g) + (1/2)O₂(g) the value of rate of disappearance of N₂O₅ is given as 6.25 × 10⁻³ mol L⁻¹ s⁻¹. The rate of formation of NO₂ and O₂ is given respectively as:
A) 1.25 × 10⁻² mol L⁻¹ s⁻¹ and 6.25 × 10⁻³ mol L⁻¹ s⁻¹
B) 6.25 × 10⁻³ mol L⁻¹ s⁻¹ and 6.25 × 10⁻³ mol L⁻¹ s⁻¹
C) 1.25 × 10⁻² mol L⁻¹ s⁻¹ and 3.125 × 10⁻³ mol L⁻¹ s⁻¹
D) 6.25 × 10⁻³ mol L⁻¹ s⁻¹ and 3.125 × 10⁻³ mol L⁻¹ s⁻¹
Explanation
[Solution from source] Rate = −d[N₂O₅]/dt = ½ d[NO₂]/dt = 2 d[O₂]/dt. So d[NO₂]/dt = 2 × 6.25 × 10⁻³ = 1.25 × 10⁻² and d[O₂]/dt = 6.25 × 10⁻³/2 = 3.125 × 10⁻³ mol L⁻¹ s⁻¹. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.