Q. If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is
A) 5.00 × 10⁻⁷ M³
B) 4.00 × 10⁻⁶ M³
C) 4.00 × 10⁻⁷ M³
D) 5.00 × 10⁻⁶ M³
Explanation
[Solution from source] pH 12 → pOH 2 → [OH⁻] = 10⁻² M. Ba(OH)₂ gives s and 2s, so s = 5 × 10⁻³ M. K_sp = s(2s)² = 5 × 10⁻³ × 10⁻⁴ = 5.00 × 10⁻⁷ M³. Using 4s³ with s = 10⁻² gives 4 × 10⁻⁶. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.