Q. Oxidation states of P in H₄P₂O₅, H₄P₂O₆, H₄P₂O₇, are respectively
A) +3, +4, +5
B) +3, +5, +4
C) +5, +3, +4
D) +5, +4, +3
Explanation
[Solution from source] With H = +1 and O = −2: H₄P₂O₅: 4 + 2x − 10 = 0, x = +3; H₄P₂O₆: x = +4; H₄P₂O₇: x = +5. So +3, +4, +5. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.