Q. The reaction of toluene with Cl₂ in presence of FeCl₃ gives X and reaction in presence of light gives Y. Thus, X and Y are
A) X = Benzyl chloride, Y = m-chlorotoluene
B) X = Benzal chloride, Y = o-chlorotoluene
C) X = m-chlorotoluene, Y = p-chlorotoluene
D) X = o- and p-chlorotoluene, Y = Trichloromethyl benzene
Explanation
[Solution from source] With FeCl₃ (Lewis acid) chlorine substitutes the ring at the o- and p-positions activated by CH₃, giving o- and p-chlorotoluene (X). In light, free-radical substitution occurs on the side chain; with excess Cl₂ this goes to C₆H₅CCl₃, trichloromethylbenzene (Y). Benzyl chloride is a side-chain product, so it cannot be X. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.