Q. Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?
A) PCl₅
B) NaOH-Br₂
C) Sodalime
D) Hot conc. H₂SO₄
Explanation
[Solution from source] Hofmann bromamide degradation: CH₃CONH₂ + Br₂ + 4NaOH → CH₃NH₂, losing one carbon. PCl₅ or hot conc. H₂SO₄ dehydrate acetamide to acetonitrile, and soda lime does not give methylamine. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.