A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] v = ω√(a² − x²) with ω = 2π/T. At x = a/2, v = (2π/T)√(3a²/4) = (2π/T)(√3a/2) = πa√3/T. The value with 2T in the denominator forgets that ω already carries the factor 2π. Answer (3).

Q. A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:

Explanation

Reviewed by Dr. Abubacker

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