Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is :

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Each rod's centre is l/2 from the axis: I = Ml²/12 + M(l/2)² = Ml²/3 (parallel-axis theorem). Four rods give 4Ml²/3. Forgetting the parallel-axis term would give only Ml²/3 for the frame. Answer (4).

Q. Four identical thin rods each of mass M and length l, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is :

Explanation

Reviewed by Dr. Abubacker

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