The Figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t₁ is the time for the planet to move from C to D and t₂ is the time to move from A to B then:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Kepler's second law: the radius vector sweeps equal areas in equal times, so time is proportional to area swept. Area SCD = 2 × area SAB gives t₁ = 2t₂. The fact that the planet moves faster near the sun is already accounted for by the equal-area law. Answer (2).

Q. The Figure shows elliptical orbit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t₁ is the time for the planet to move from C to D and t₂ is the time to move from A to B then:

Explanation

Reviewed by Dr. Abubacker

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