Q. Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be:
A) 3C, V/3
B) C/3, 3V
C) 3C, 3V
D) C/3, V/3
Explanation
[Solution from source] Capacitors in series: 1/C_eq = 3/C, so C_eq = C/3. The same charge sits on each, so the applied voltage divides equally and each can take V before breakdown: total 3V. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.