A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] From rest under constant force, S = ½at², so S ∝ t². Doubling the time from 10 s to 20 s makes S₂ = 4S₁. S₂ = 3S₁ is the distance in the second 10 s, not the total. Answer (2).

Q. A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:

Explanation

Reviewed by Dr. Abubacker

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