Q. The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between:
A) n = 3 to n = 1 states
B) n = 2 to n = 1 states
C) n = 4 to n = 3 states
D) n = 3 to n = 2 states
Explanation
[Solution from source] Number of lines from level n = n(n − 1)/2 = 6, so n = 4. The longest wavelength needs the smallest energy gap, which is between n = 4 and n = 3. The 3 → 1 or 2 → 1 lines have larger gaps and shorter wavelengths. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.