The state of hybridization of C2, C3, C5 and C6 of the hydrocarbon CH₃–C(CH₃)₂–CH=CH–CH(CH₃)–C≡CH (numbered from the right: C≡CH carbons are C1 and C2, the CH(CH₃) carbon is C3, CH=CH are C4 and C5, the C(CH₃)₂ carbon is C6, end CH₃ is C7) is in the following sequence:

Question

Dr. Abubacker · Accepted Answer

[Solution from source] C2 is a triple-bonded carbon (sp). C3 is the CH(CH₃) carbon with only single bonds (sp³). C5 is a double-bonded carbon (sp²). C6 is the quaternary C(CH₃)₂ carbon (sp³). So the sequence is sp, sp³, sp², sp³. Answer (4).

Q. The state of hybridization of C2, C3, C5 and C6 of the hydrocarbon CH₃–C(CH₃)₂–CH=CH–CH(CH₃)–C≡CH (numbered from the right: C≡CH carbons are C1 and C2, the CH(CH₃) carbon is C3, CH=CH are C4 and C5, the C(CH₃)₂ carbon is C6, end CH₃ is C7) is in the following sequence:

Explanation

Reviewed by Dr. Abubacker

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