Q. Oxidation numbers of P in PO₄³⁻, of S in SO₄²⁻ and that of Cr in Cr₂O₇²⁻, are respectively :
A) +3, +6 and +5
B) +5, +3 and +6
C) −3, +6 and +6
D) +5, +6 and +6
Explanation
[Solution from source] PO₄³⁻: x − 8 = −3, x = +5. SO₄²⁻: x − 8 = −2, x = +6. Cr₂O₇²⁻: 2x − 14 = −2, x = +6. So +5, +6 and +6. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.