Q. For the reaction N₂ + 3H₂ → 2NH₃, if d[NH₃]/dt = 2 × 10⁻⁴ mol L⁻¹ s⁻¹, the value of −d[H₂]/dt would be :
A) 4 × 10⁻⁴ mol L⁻¹ s⁻¹
B) 6 × 10⁻⁴ mol L⁻¹ s⁻¹
C) 1 × 10⁻⁴ mol L⁻¹ s⁻¹
D) 3 × 10⁻⁴ mol L⁻¹ s⁻¹
Explanation
[Solution from source] Rate = −(1/3)d[H₂]/dt = (1/2)d[NH₃]/dt. So −d[H₂]/dt = (3/2) × 2 × 10⁻⁴ = 3 × 10⁻⁴ mol L⁻¹ s⁻¹. Multiplying by 3 alone gives 6 × 10⁻⁴. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.