A 0.0020 m aqueous solution of an ionic compound Co(NH₃)₅(NO₂)Cl freezes at −0.00732 °C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (Kf = −1.86 °C/m)

Question

Dr. Abubacker · Accepted Answer

[Solution from source] ΔTf = iKf m, so i = 0.00732/(1.86 × 0.0020) ≈ 1.97 ≈ 2. The compound is [Co(NH₃)₅(NO₂)]Cl, giving one complex cation and one Cl⁻ ion. A value of 3 would need two ionisable chlorides. Answer (4).

Q. A 0.0020 m aqueous solution of an ionic compound Co(NH₃)₅(NO₂)Cl freezes at −0.00732 °C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (Kf = −1.86 °C/m)

Explanation

Reviewed by Dr. Abubacker

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