Q. Predict the product : C₆H₅–NHCH₃ + NaNO₂ + HCl → Product
A) C₆H₅–N(CH₃)–NO₂
B) Mixture of o- and p-nitroso-N-methylaniline (ON–C₆H₄–NHCH₃)
C) C₆H₅–N(OH)–CH₃
D) C₆H₅–N(CH₃)–N=O
Explanation
[Solution from source] N-methylaniline is a secondary amine; with HNO₂ (from NaNO₂ + HCl) the N–H hydrogen is replaced by –N=O, giving N-nitroso-N-methylaniline, C₆H₅N(CH₃)–N=O. Ring nitrosation happens with tertiary aromatic amines such as N,N-dimethylaniline. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.