[Solution from source] CH₂=CH–C≡CH: numbering from the double-bond end gives the double bond at C1 and the triple bond at C3, and when locants tie the double bond gets the lower number. The name is but-1-en-3-yne, written here as 1-butene-3-yne. Names with 'yne' cited first are wrong since 'ene' precedes 'yne'. Answer (3).