Q. For the reaction A + B → products, it is observed that: (a) on doubling the initial concentration of A only, the rate of reaction is also doubled and (b) on doubling the initial concentrations of both A and B, there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is given by:
A) rate = k[A][B]²
B) rate = k[A]²[B]²
C) rate = k[A][B]
D) rate = k[A]²[B]
Explanation
[Solution from source] Doubling [A] alone doubles the rate, so the order in A is 1. Doubling both raises the rate 8 times: 2¹ × 2ⁿ = 8, so n = 2 for B. Rate = k[A][B]². Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.