Q. If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be
A) 2%
B) 4%
C) 6%
D) 8%
Explanation
[Solution from source] V = (4/3)πr³, so ΔV/V = 3(Δr/r) = 3 × 2% = 6%. Taking 8% would wrongly cube the error itself instead of multiplying it by the power 3. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.