Q. The distance travelled by a particle starting from rest and moving with an acceleration (4/3) m s⁻², in the third second is
A) 19/3 m
B) 6 m
C) 4 m
D) 10/3 m
Explanation
[Solution from source] Distance in the nth second from rest = (a/2)(2n − 1) = (2/3)(2 × 3 − 1) = 10/3 m. 6 m is the total distance covered in the first three seconds, (1/2)(4/3)(3²), not the distance in the third second alone. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.