Q. A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 m s⁻¹ to 20 m s⁻¹ while passing through a distance 135 m in t second. The value of t is

A) 9
B) 10
C) 1.8
D) 12
Explanation

[Solution from source] For uniform acceleration s = (u + v)t/2, so 135 = (10 + 20)t/2 and t = 9 s. Check: a = (20² − 10²)/(2 × 135) = 10/9 m s⁻², and (20 − 10)/(10/9) = 9 s. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want to attempt the full paper?
View Full Paper Take Full Paper Online