Q. A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be

A) zero
B) 2mv
C) mv/√2
D) mv√2
Explanation

[Solution from source] The horizontal momentum mv cos 45° is unchanged, while the vertical component mv sin 45° reverses. The change is 2mv sin 45° = √2 mv. The answer is not zero, because momentum is a vector and its direction has changed even though the speed is the same. Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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