Q. At 10°C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110°C this ratio is
A) (283/383)x
B) x
C) (383/283)x
D) (10/110)x
Explanation
[Solution from source] From PV = (m/M)RT, ρ/P = M/(RT), so the ratio is inversely proportional to absolute temperature. At 383 K it becomes x × 283/383. Using Celsius temperatures (10/110) is wrong because gas laws need kelvin. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.