Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations of two points?

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Wavelength λ = vT = 300 × 0.05 = 15 m. Path difference = 15 − 10 = 5 m, so phase difference = (2π/λ) × 5 = 2π/3. Using λ = 5 m by mistake would give 2π, not one of the options. Answer (3).

Q. Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations of two points?

Explanation

Reviewed by Dr. Abubacker

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