Q. The values of Kp₁ and Kp₂ for the reactions X ⇌ Y + Z ....(1) and A ⇌ 2B ....(2) are in ratio of 9 : 1. If degree of dissociation of X and A be equal, then total pressure at equilibrium (1) and (2) are in the ratio

A) 1 : 1
B) 3 : 1
C) 1 : 9
D) 36 : 1
Explanation

[Solution from source] With degree of dissociation α: for the first reaction, moles 1 − α, α, α (total 1 + α) give Kp₁ = α²P₁/(1 − α²). For the second reaction, moles 1 − α, 2α (total 1 + α) give Kp₂ = 4α²P₂/(1 − α²). Then Kp₁/Kp₂ = P₁/(4P₂) = 9, so P₁ : P₂ = 36 : 1. 9 : 1 would forget the factor 4 from (2α)². Answer (4).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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