Q. How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?
A) 0.029
B) 0.044
C) 0.333
D) 0.011
Explanation
[Solution from source] PbO + 2HCl → PbCl₂ + H₂O. Moles of PbO = 6.5/223 ≈ 0.029, and of HCl = 3.2/36.5 ≈ 0.088, more than the 0.058 needed. PbO is the limiting reagent, so 0.029 mol PbCl₂ forms. 0.044 would wrongly treat HCl as limiting (0.088/2). Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.