Q. Volume occupied by one molecule of water (density = 1 g cm⁻³) is
A) 5.5 × 10⁻²³ cm³
B) 9.0 × 10⁻²³ cm³
C) 6.023 × 10⁻²³ cm³
D) 3.0 × 10⁻²³ cm³
Explanation
[Solution from source] One mole of water (18 g) occupies 18 cm³ at density 1 g cm⁻³. Volume per molecule = 18/(6.022 × 10²³) ≈ 3.0 × 10⁻²³ cm³. 6.023 × 10⁻²³ cm³ just reuses the digits of Avogadro's number. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.