Q. Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate completely in acidic medium will be
A) 0.2 moles
B) 0.6 moles
C) 0.4 moles
D) 7.5 moles
Explanation
[Solution from source] In FeC₂O₄ both parts are oxidised: Fe²⁺ → Fe³⁺ (1 e⁻) and C₂O₄²⁻ → 2CO₂ (2 e⁻), so 3 electrons per mole. Each MnO₄⁻ → Mn²⁺ takes 5 electrons, so 3/5 = 0.6 mol MnO₄⁻ is needed. 0.4 mol counts only the oxalate electrons. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.