Q. In the hydrocarbon CH₃(6)–CH(5)=CH(4)–CH₂(3)–C(2)≡CH(1) The state of hybridization of carbons 1, 3 and 5 are in the following sequence
A) sp³, sp², sp
B) sp², sp, sp³
C) sp, sp³, sp²
D) sp, sp², sp³
Explanation
[Solution from source] C-1 is part of the C≡C triple bond (sp), C-3 is a CH₂ with only single bonds (sp³), and C-5 is part of the C=C double bond (sp²). The sp, sp², sp³ sequence wrongly gives C-3 a double bond. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.