Q. An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be
A) CH₄O
B) CH₃O
C) CH₂O
D) CHO
Explanation
[Solution from source] O = 100 − 38.71 − 9.67 = 51.62%. Moles: C = 38.71/12 = 3.23, H = 9.67/1 = 9.67, O = 51.62/16 = 3.23, a ratio of 1 : 3 : 1, so the empirical formula is CH₃O. CH₄O (methanol) would need about 12.5% H. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.