The position x of a particle with respect to time t along x-axis is given by x = 9t² − t³ where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the +ve x direction?

Question

Dr. Abubacker · Accepted Answer

[Solution from source] v = dx/dt = 18t − 3t² and a = 18 − 6t; speed is maximum when a = 0, i.e. t = 3 s. Then x = 9(9) − 27 = 54 m. 81 m is just the 9t² term without subtracting t³. Answer (1).

Q. The position x of a particle with respect to time t along x-axis is given by x = 9t² − t³ where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the +ve x direction?

Explanation

Reviewed by Dr. Abubacker

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