Q. If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm, then ¹²⁵₃₂Te would have its radius approximately as
A) 9.6 fm
B) 12.0 fm
C) 4.8 fm
D) 6.0 fm
Explanation
[Solution from source] R ∝ A^(1/3), so R_Te = 3.6 × (125/27)^(1/3) = 3.6 × 5/3 = 6.0 fm. Scaling the radius in proportion to A instead of its cube root would give a much larger value. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.