Q.
A particle moving along x-axis has acceleration f, at time t, given by f = f₀(1 − t/T), where f₀ and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle's velocity (vx) is
A) (1/2)f₀T²
B) f₀T²
C) (1/2)f₀T
D) f₀T
Explanation
[Solution from source] f = 0 at t = T. v = ∫₀ᵀ f₀(1 − t/T) dt = f₀T − f₀T/2 = ½f₀T. f₀T would be the velocity if the acceleration stayed at f₀ throughout. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.