Q. The particle executing simple harmonic motion has a kinetic energy K₀ cos² ωt. The maximum values of the potential energy and the total energy are respectively

A) K₀/2 and K₀
B) K₀ and 2K₀
C) K₀ and K₀
D) 0 and 2K₀
Explanation

[Solution from source] Kinetic energy is maximum (K₀) at the mean position, where all energy is kinetic, so total energy = K₀. Potential energy is maximum at the extremes and also equals K₀. 2K₀ wrongly adds the two maxima. Answer (3).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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