Q. The total energy of electron in the ground state of hydrogen atom is – 13.6 eV. The kinetic energy of an electron in the first excited state is
A) 6.8 eV
B) 13.6 eV
C) 1.7 eV
D) 3.4 eV
Explanation
[Solution from source] En = −13.6/n² eV, so in the first excited state (n = 2) E = −3.4 eV. For a Bohr orbit kinetic energy = −E = 3.4 eV. 13.6 eV is the ground-state value. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.