Q. A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
A) T/8
B) T/12
C) T/2
D) T/4
Explanation
[Solution from source] x = a sin ωt; x = a/2 when ωt = π/6, so t = (π/6)/(2π/T) = T/12. T/4 is the time to reach the full amplitude. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.