Q. A steady current of 1.5 amp flows through a copper voltameter for 10 minutes. If the electrochemical equivalent of copper is 30 × 10⁻⁵ g coulomb⁻¹, the mass of copper deposited on the electrode will be
A) 0.50 g
B) 0.67 g
C) 0.27 g
D) 0.40 g
Explanation
[Solution from source] Faraday's first law: m = ZIt = 30 × 10⁻⁵ × 1.5 × 600 = 0.27 g. Forgetting to convert 10 minutes to 600 s gives a far smaller value. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.