Q.
A weak acid, HA, has a Ka of 1.00 × 10⁻⁵. If 0.100 mole of this acid dissolved in one litre of water, the percentage of acid dissociated at equilibrium is closest to
A) 1.00%
B) 99.9%
C) 0.100%
D) 99.0%
Explanation
[Solution from source] α = √(Ka/C) = √(1.00 × 10⁻⁵/0.100) = 1.00 × 10⁻², i.e. 1.00%. 0.100% would come from Ka/C without the square root. Answer (1).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.