Q. Consider the following compounds. (i) C₆H₅COCl (ii) O₂N–C₆H₄–COCl (para) (iii) H₃C–C₆H₄–COCl (para) (iv) OHC–C₆H₄–COCl (para) The correct decreasing order of their reactivity towards hydrolysis is
A) (i) > (ii) > (iii) > (iv)
B) (iv) > (ii) > (i) > (iii)
C) (ii) > (iv) > (i) > (iii)
D) (ii) > (iv) > (iii) > (i)
Explanation
[Solution from source] Hydrolysis is a nucleophilic attack at the carbonyl carbon, faster when electron-withdrawing groups make it more positive. –NO₂ withdraws more strongly than –CHO, H is neutral and –CH₃ donates, so (ii) > (iv) > (i) > (iii). Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.