Q. The equilibrium constant of the reaction: Cu(s) + 2Ag⁺(aq) → Cu²⁺(aq) + 2Ag(s) ; E° = 0.46 V at 298 K is
A) 2.0 × 10¹⁰
B) 4.0 × 10¹⁰
C) 4.0 × 10¹⁵
D) 2.4 × 10¹⁰
Explanation
[Solution from source] log K = nE°/0.0591 = 2 × 0.46/0.0591 = 15.57, so K = 10¹⁵·⁵⁷ ≈ 3.7 × 10¹⁵ ≈ 4.0 × 10¹⁵. Taking n = 1 would give a value near 10⁸. Answer (3).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.