An element, X has the following isotopic composition: ²⁰⁰X : 90%, ¹⁹⁹X : 8.0%, ²⁰²X : 2.0% The weighted average atomic mass of the naturally occurring element X is closest to

Question

Dr. Abubacker · Accepted Answer

[Solution from source] Average mass = 200 × 0.90 + 199 × 0.08 + 202 × 0.02 = 180 + 15.92 + 4.04 = 199.96 ≈ 200 amu. 201 amu would be a simple average of the three masses. Answer (4).

Q. An element, X has the following isotopic composition: ²⁰⁰X : 90%, ¹⁹⁹X : 8.0%, ²⁰²X : 2.0% The weighted average atomic mass of the naturally occurring element X is closest to

Explanation

Reviewed by Dr. Abubacker

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