Q. The fraction of total volume occupied by the atoms present in a simple cube is
A) π/(3√2)
B) π/(4√2)
C) π/4
D) π/6
Explanation
[Solution from source] A simple cube has 1 atom per cell with a = 2r, so packing fraction = (4/3)πr³/(2r)³ = π/6 ≈ 0.52. π/(3√2) is the value for fcc. Answer (4).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.