Q. The binding energy of deuteron is 2.2 MeV and that of ⁴₂He is 28 MeV. If two deuterons are fused to form one ⁴₂He then the energy released is :
A) 21.6 MeV
B) 23.6 MeV
C) 17.2 MeV
D) 28.2 MeV
Explanation
[Solution from source] Energy released = binding energy of products − binding energy of reactants = 28 − 2 × 2.2 = 23.6 MeV. Subtracting the binding energy of only one deuteron gives 25.8 MeV, and adding them gives 32.4 MeV, neither of which applies. Answer (2).
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.